GPL libraries have an advantage in their legal power. MIT libraries have an advantage when users have to choose between 2 libraries.
All other things being equal, users will use more permissive libraries. So unless maintainers put more effort into the GPL, a MIT one will gather more users, which attracts more maintainers, which ends up in more MIT libraries than GPL ones existing.
Probably because rust links statically by default, so making a library gpl means users will be forced to make their project GPL too, so MIT libraries have an incredible advantage.
I’m sorry, no wonder you are lost, so it made no sense when you wrote this comment, lemmy deleted everything between the “less than” character and “>”. I had to change them for “<” in order for them not to get deleted.
I want to do basically this:
```rust
struct MyStruct < T> {
data: T
}
impl < T> for MyStruct < T> {
fn foo() {
println!("Generic")
}
}
impl for MyStruct < u32> {
fn foo() {
println!("u32")
}
}
```
I have tried doing
```rust
impl < T: !u32> for MyStruct < T> {
...
}
```
But it doesn't seem to work. I've also tried various things with traits but none of them seem to work. Is this even possible?
EDIT: Fixed formatting
The lifetime extension is huge.